Python Project: Check if Number is Even or Odd

Level: Beginner

Project Overview 💡

In this beginner-friendly project, you’ll write a Python program that checks whether a number entered by the user is even or odd. This is a great way to practice input handling, number conversion, and conditional logic.

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Challenge Yourself! 🚀

Before checking the solution, try writing a script that takes a number and prints whether it is even or odd.

Task:

Write a Python program that:

• Asks the user to input a number

• Converts it from string to integer

• Uses the modulus operator to determine if it's even or odd

• Prints the result accordingly

Expected Output:
(1) The program prompts the user to enter a number in the terminal:

(2) The user types in a number (e.g., 3) and presses Enter. The program checks the number and prints out either “The number X is odd.” or “The number X is even.” depending on the number:

Give it a shot! Scroll down when you're ready for the step-by-step guide.

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Spoiler Alert!

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Step-by-Step Guide

Step 1️⃣: Get User Input

Use the input() function to get a number from the user as a string.

number = input("Enter a number: ")

Step 2️⃣: Convert to Integer

Convert the input string to an integer using int().

number = int(number)

Step 3️⃣: Use Modulus to Check Even/Odd

Use % to check if the number is divisible by 2.

if number % 2 == 0:

Step 4️⃣: Display Result for Even

If divisible by 2, the number is even.

    print(f"The number {number} is even.")

Step 5️⃣: Display Result for Odd

If not, it's odd.

else:
    print(f"The number {number} is odd.")

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Complete Code 🧨

# Step 1: Get user input
number = input("Enter a number: ")

# Step 2: Convert input to an integer
number = int(number)

# Step 3: Check if the number is even or odd
if number % 2 == 0:
    # Step 4: Display the result if the number is even
    print(f"The number {number} is even.")
else:
    # Step 5: Display the result if the number is odd
    print(f"The number {number} is odd.")

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Alternative Solution

Here’s a version that includes error handling to prevent crashes if the user enters a non-numeric value:

try:
    number = int(input("Enter a number: "))
    if number % 2 == 0:
        print(f"The number {number} is even.")
    else:
        print(f"The number {number} is odd.")
except ValueError:
    print("That's not a valid number. Please enter an integer.")

Comparison

• The original version is concise and good for clean input.

• The alternative version is more user-proof by handling errors gracefully.

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